Revision as of 13:27, 8 October 2008 by Cztan (Talk)

Let $ x(t) = e^{-a(t+1)} u(t + 1) $

$ \chi(w) = \mathcal{F} (x(t)) = \int^{\infty}_{-\infty} e^{-at}e^{-a} u(t + 1) e^{-jwt} dt $

$ = e^{-a} \int^{\infty}_{-1} e^{-at}.e^{-jwt} dt $

$ = e^{-a} \int^{\infty}_{-1}e^{-(a+jw)t} dt $

$ = -\frac{e^{-a}}{a+jw} [e^{-(a+jw)t}]^{\infty}_{0} $

$ = -\frac{e^{-a}}{a+jw} [-e^{a+jw}] $

$ =\frac{e^{-(2a+jw)}}{a+jw} $

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal