(New page: == 6.(A) == This is not time-invariant.<br> 1. input(<math>/delta[n-k]</math>) -> system -> time delay -> output : <math>(k+1)^2/delta[n-(k+2)]</math><br> 2. input(<math>/delta[n-k]</mat...)
 
(6.(A))
Line 3: Line 3:
 
This is not time-invariant.<br>
 
This is not time-invariant.<br>
  
1. input(<math>/delta[n-k]</math>) -> system -> time delay -> output : <math>(k+1)^2/delta[n-(k+2)]</math><br>
+
1. input(<math>/delta[n-k]</math>) -> system -> time delay -> output : <math>(k+1)^2\delta[n-(k+2)]</math><br>
2. input(<math>/delta[n-k]</math>) -> time delay -> system -> output : <math>(k+2)^2/delta[n-(k+2)]</math><br>
+
2. input(<math>/delta[n-k]</math>) -> time delay -> system -> output : <math>(k+2)^2\delta[n-(k+2)]</math><br>
  
 
The output signals are different each other. So this is not time-invariant.
 
The output signals are different each other. So this is not time-invariant.

Revision as of 18:46, 10 September 2008

6.(A)

This is not time-invariant.

1. input($ /delta[n-k] $) -> system -> time delay -> output : $ (k+1)^2\delta[n-(k+2)] $
2. input($ /delta[n-k] $) -> time delay -> system -> output : $ (k+2)^2\delta[n-(k+2)] $

The output signals are different each other. So this is not time-invariant.

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang