(Energy)
(Energy)
Line 11: Line 11:
 
<math>=\int_0^{2\pi}{(2(2cos(t)^2-1)+2)dt}</math>
 
<math>=\int_0^{2\pi}{(2(2cos(t)^2-1)+2)dt}</math>
  
<math>=\int_0^{2\pi}{2+cos(2t))dt</math>
+
<math>=\int_0^{2\pi}{2+cos(2t))dt}</math>
  
 
<math>=(2t+sin(2t))|_{t=0}^{t=2\pi}</math>
 
<math>=(2t+sin(2t))|_{t=0}^{t=2\pi}</math>
Line 17: Line 17:
 
<math>=(4\pi+0-0-0)</math>
 
<math>=(4\pi+0-0-0)</math>
  
<math>=4\pi</math>
+
<math>=(4\pi)</math>

Revision as of 15:42, 3 September 2008

Signal

$ y(t)=2cos(t) $

Energy

We will find the energy in one cycle of the cosine waveform.

$ E=\int_0^{2\pi}{|2cos(t)|^2dt} $

$ =\int_0^{2\pi}{(2(2cos(t)^2-1)+2)dt} $

$ =\int_0^{2\pi}{2+cos(2t))dt} $

$ =(2t+sin(2t))|_{t=0}^{t=2\pi} $

$ =(4\pi+0-0-0) $

$ =(4\pi) $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang