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To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.
 
To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.
  
<math>\frac{d}{dp}(p^4(1-p)^6) = 2*p^3(p-1)^5(5p - 2)</math>
+
<math>\frac{d}{dp}(p^4(1-p)^6) = 2p^3(p-1)^5(5p - 2)</math>
  
 
<math>2*p^3(p-1)^5(5p - 2) = 0, p = 2/5</math>
 
<math>2*p^3(p-1)^5(5p - 2) = 0, p = 2/5</math>

Latest revision as of 19:25, 4 November 2008

Let O=TTHHTHTTHT

and knowing p=P[head]

$ P[O;p] = p^4(1-p)^6 $

$ P_{ML}=max(p^4(1-p)^6) $

To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.

$ \frac{d}{dp}(p^4(1-p)^6) = 2p^3(p-1)^5(5p - 2) $

$ 2*p^3(p-1)^5(5p - 2) = 0, p = 2/5 $

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009