Line 11: Line 11:
 
\left ( \frac{1}{jk\omega_0} \right )a_k
 
\left ( \frac{1}{jk\omega_0} \right )a_k
 
=
 
=
\left ( \frac{1}{jk \left (2\pi/T \right)} \right )
+
\left ( \frac{1}{jk \left (2\pi/T \right)} \right )a_k
 
</math>
 
</math>

Revision as of 13:00, 26 September 2008

The function y(t) in this example is the signal equal to the periodic continuous-time integral of cos(x) such that

$ y(t) = \int_{-\infty}^{t} cos(x)\, dx $

where its Fourier series coefficients are described by the equation

$ \left ( \frac{1}{jk\omega_0} \right )a_k = \left ( \frac{1}{jk \left (2\pi/T \right)} \right )a_k $

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal