(→h[n] and H(z)) |
|||
| Line 12: | Line 12: | ||
<math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup> | <math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup> | ||
| − | <math> \,\ H[z] = \sum_{m=-6}^{5} | + | <math> \,\ H[z] = \sum_{m=-6}^{5}Z</math><sup>(<math>-m</math>)</sup> |
Revision as of 16:18, 25 September 2008
Define a DT LTI System
$ \,\ x[n] = 5*u[n-5] + 6*u[n+6] $
h[n] and H(z)
We obtain $ h[n] $ by finding the response of $ x[n] $ to the unit impulse response ($ \delta[n] $).
$ \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] $
$ \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z $($ -m $) $ \,\ H[z] = \sum_{m=-6}^{5}Z $($ -m $)
