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**Author answer here | **Author answer here | ||
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| − | * Review by | + | * Review by Sahil Sanghani |
| − | ** | + | ** I really liked your slecture. Showing how <math>e^{-j2{\pi}n} = 1</math> was really helpful. Also showing the common mistake students make in continuous time was useful. You really showed the necessity for the guess and check method in this derivation. Overall this was a great slecture that was easy to follow and understand. |
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* Review by student 4 | * Review by student 4 | ||
Revision as of 17:34, 14 October 2014
Questions and Comments for
Please post your reviews, comments, and questions below.
- Review by Jacob Holtman
There is a lot of good work but some of the data seems extra such as e^− j2πn = 1 which can be said is true only when n is an integer and not any real number. In the example it would be good to mention the sifting property for the integral of a delta. I like how the reasoning is explained for the work and why the idft is used unlike the dft.
- Author answer here
- Review by Andrew Pawling
Really great explanation. I like how you showed the common mistake that student make with continuous signals. The slecture could be improved with some graphical examples. I disagree and think showing e^− j2πn = 1 is helpful. It will always be true in this case since we are working in discrete time. If you didn't realize this the simplification of the sum could be confusing.
- Author answer here
- Review by Sahil Sanghani
- I really liked your slecture. Showing how $ e^{-j2{\pi}n} = 1 $ was really helpful. Also showing the common mistake students make in continuous time was useful. You really showed the necessity for the guess and check method in this derivation. Overall this was a great slecture that was easy to follow and understand.
- Review by student 4
- Author answer here
- Review by student 5
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- Review by student 6
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- Review by student 7
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- Review by student 8
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- Review by student 9
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- Review by student 10
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