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<math>\,\!(a+bi)+(c+di)=(a+c)+i(b+d)</math>
 
<math>\,\!(a+bi)+(c+di)=(a+c)+i(b+d)</math>
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An example would be:
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<math>\,\!(5+2i)+(3-i)=8+i</math>
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== Multiplying ==
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Complex numbers are multiplied using the standard distributive properties, but remembering that <math>\,\!i^2=-1</math>.
 +
 +
General case:
 +
 +
<math>\,\!(a+bi)*(c+di)=ac-bd+i(ad+bc)</math>
 +
 +
An example is:
 +
<math>\,\!(1+2i)*(4-i)=4-i+8i+2=6+7i</math>
 +
 +
 +
== Complex Conjugate ==
 +
Oftentimes the imaginary part of a complex number must be eliminated from a fraction. This is accomplished by multiplying both the numerator and denominator by a complex conjugate. If the complex number is of the form <math>\,\!a+bi</math>, then the complex conjugate of that number is <math>\,\!a-bi</math>, or the imaginary part is made negative.
 +
 +
General case:
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 +
<math>\,\!(a+bi)(a-bi)=a^2+b^2</math>
 +
 +
This has practical applications for graphing complex numbers.
 +
 +
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==
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== Headline text ==
 +
==

Revision as of 17:23, 3 September 2008

Complex number basics and examples

Background and Form

Complex numbers are written in the form $ a+bi $, where a is the "real" part of the number and b is the "imaginary" part. The variable that denotes the imaginary part of the complex number is $ i $, where

$ i=\sqrt{-1} $ and $ \,\!i^2=-1 $

The real part of the number is thought of as lying on the x axis, while the imaginary lies on the y axis, so $ \,\!a+bi $ can also be graphed as a vector. This has special pertinence to Euler's formula, which relates sinusoidal and exponential equations using the complex number plane, but this is outside our scope.

Adding

Complex numbers are added by separating their real and imaginary parts, and adding them separately. The general case is:

$ \,\!(a+bi)+(c+di)=(a+c)+i(b+d) $

An example would be:

$ \,\!(5+2i)+(3-i)=8+i $


Multiplying

Complex numbers are multiplied using the standard distributive properties, but remembering that $ \,\!i^2=-1 $.

General case:

$ \,\!(a+bi)*(c+di)=ac-bd+i(ad+bc) $

An example is: $ \,\!(1+2i)*(4-i)=4-i+8i+2=6+7i $


Complex Conjugate

Oftentimes the imaginary part of a complex number must be eliminated from a fraction. This is accomplished by multiplying both the numerator and denominator by a complex conjugate. If the complex number is of the form $ \,\!a+bi $, then the complex conjugate of that number is $ \,\!a-bi $, or the imaginary part is made negative.

General case:

$ \,\!(a+bi)(a-bi)=a^2+b^2 $

This has practical applications for graphing complex numbers.


==

Headline text

==

Alumni Liaison

Prof. Math. Ohio State and Associate Dean
Outstanding Alumnus Purdue Math 2008

Jeff McNeal