Line 5: Line 5:
  
 
[5  0  0]
 
[5  0  0]
 +
 
[4  1  0]
 
[4  1  0]
 +
 
[3  2  0]
 
[3  2  0]
 +
 
[3  1  1]
 
[3  1  1]
 +
 
[2  2  1]
 
[2  2  1]
  
 
Hence 5 is the answer.
 
Hence 5 is the answer.

Revision as of 15:30, 28 September 2008

The total number of ways could be found by innumerating all the possible cases, which are

B1 B2 B3

[5 0 0]

[4 1 0]

[3 2 0]

[3 1 1]

[2 2 1]

Hence 5 is the answer.

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin