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=1.3 Bayes' theorem=
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From the [[ECE_600_Prerequisites|ECE600 Pre-requisites notes]] of  [[user:han84|Sangchun Han]], [[ECE]] PhD student.
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• = Bayes' rule
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• <math class="inline">P\left(A|B\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)}=\frac{P\left(B|A\right)P\left(A\right)}{P\left(B\right)}</math>
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• If <math class="inline">P\left(B\right)=\sum_{i}P\left(B\cap A_{i}\right)=\sum_{i}P\left(B|A_{i}\right)P\left(A_{i}\right)</math> , then <math class="inline">P\left(A_{i}|B\right)=\frac{P\left(A_{i}\cap B\right)}{P\left(B\right)}=\frac{P\left(B|A_{i}\right)A_{i}}{\sum_{j}P\left(B|A_{j}\right)A_{j}}</math>
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[[ECE600|Back to ECE600]]
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[[ECE 600 Prerequisites|Back to ECE 600 Prerequisites]]

Latest revision as of 11:23, 30 November 2010

1.3 Bayes' theorem

From the ECE600 Pre-requisites notes of Sangchun Han, ECE PhD student.


• = Bayes' rule

$ P\left(A|B\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)}=\frac{P\left(B|A\right)P\left(A\right)}{P\left(B\right)} $

• If $ P\left(B\right)=\sum_{i}P\left(B\cap A_{i}\right)=\sum_{i}P\left(B|A_{i}\right)P\left(A_{i}\right) $ , then $ P\left(A_{i}|B\right)=\frac{P\left(A_{i}\cap B\right)}{P\left(B\right)}=\frac{P\left(B|A_{i}\right)A_{i}}{\sum_{j}P\left(B|A_{j}\right)A_{j}} $


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