Difference between revisions of "CT Fourrier Coefficients ECE301Fall2008mboutin" - Rhea

Latest revision as of 10:33, 12 October 2008

$ak = \frac{1}{T} \int_{0}^{T}x(t)e^{-jk} \frac{2\pi}{T} dt$

Revision as of 10:32, 12 October 2008 (view source) Amelnyk (Talk) ← Older edit		Latest revision as of 10:33, 12 October 2008 (view source) Amelnyk (Talk)
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−	<math> ak = \frac{1}{T} \int_{0}^{T}x(t)e^{-jk\~~omega _~~{o}t}dt</math>	+	<math> ak = \frac{1}{T} \int_{0}^{T}x(t)e^{-jk} \frac{2\pi}{T} dt</math>