(New page: I like to think of it like the Monty Hall problem. Once we know we have a red side, there are only 2 red sides left. So then, what's the chance that one of them is on the back of your ch...) |
(No difference)
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Latest revision as of 05:38, 10 September 2008
I like to think of it like the Monty Hall problem. Once we know we have a red side, there are only 2 red sides left. So then, what's the chance that one of them is on the back of your chosen card?
