Line 9: Line 9:
 
</pre>
 
</pre>
 
<math> E \,\!</math>
 
<math> E \,\!</math>
<math>= \sum_{n=0}^\inf \left | \frac{a}{b} \right | </math>
+
<math>= \sum_{n=0}^\inf \left | \frac{x(n)}{1} \right | ^2 </math>
 
+
<math>= \left | \frac{a}{b} \right |
+

Revision as of 18:56, 5 September 2008

Energy of a CT Signal

$ Energy = \int_{t1}^{t2} \left | \frac{x}{1} \right |\ ^2 dx $

Energy of a DT Signal

$ E \,\! $ $ = \sum_{n=0}^\inf \left | \frac{x(n)}{1} \right | ^2 $

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