(New page: <math>Vmcos(\omega t+ \phi) = Acos(\omega t)+Bsin(\omega t)\,</math> <math>Vm = \sqrt {A^2+B^2}</math> and <math>\,\ \phi= \tan^{-1} \frac{-B}{A}\,</math> Differentiation Property <math...) |
(No difference)
|
Latest revision as of 17:13, 5 September 2008
$ Vmcos(\omega t+ \phi) = Acos(\omega t)+Bsin(\omega t)\, $
$ Vm = \sqrt {A^2+B^2} $ and $ \,\ \phi= \tan^{-1} \frac{-B}{A}\, $
Differentiation Property $ \,\ \frac{d}{dt}Re[A e ^{j \omega t}] = Re [\frac{d}{dt} (A e ^{j \omega t})]=Re[j \omega A e^{j \omega t}] $
