(New page: Energy of 2cos(t) E = <math> \int_{0}^{2\pi} \vert 2cos(t) \vert^2 \ , dx</math> = <math> 4/2 \int_{0}^{2\pi} (1 + 2cos(t)) \ , dx</math> = 2(t + sin(2t)) = <math>2\pi<...) |
(No difference)
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Latest revision as of 17:12, 5 September 2008
Energy of 2cos(t)
E = $ \int_{0}^{2\pi} \vert 2cos(t) \vert^2 \ , dx $
= $ 4/2 \int_{0}^{2\pi} (1 + 2cos(t)) \ , dx $
= 2(t + sin(2t))
= $ 2\pi $
Power of 2cos(t)
P = $ 1/2\pi \int_{0}^{2\pi} \vert 2cos(t) \vert^2 \ , dx $
= $ 4/4\pi \int_{0}^{2\pi} (1 + 2cos(t)) \ , dx $
= $ 1/\pi(2\pi + 0) $
= 2
