(New page: =Signal Power= The average power over an interval of time <math>[t_1,t_2]\!</math> is <math>P_{avg}=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\ dt \!</math>. Given that <math>y(t) = cos(2...) |
(No difference)
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Revision as of 10:28, 5 September 2008
Signal Power
The average power over an interval of time $ [t_1,t_2]\! $ is $ P_{avg}=\frac{1}{t_2-t_1}\int_{t_1}^{t_2} |x(t)|^2\ dt \! $.
Given that $ y(t) = cos(2*pi*t) \! $ and time interval $ [0,2]\! $, 1/(2-0)
Signal Energy
The equation to calculate signal energy is as follows: $ E=\int_{t_1}^{t_2}x(t)dt $
using the same equation $ y(t) = cos(2*pi*t) \! $ over a time interval $ [0,2]\! $ as the previous section,
