Line 6: Line 6:
 
== Signal Power ==
 
== Signal Power ==
 
For CT functions, the power of a signal from <math>t_1\!</math> to <math>t_2\!</math> is given by the function <math>P_{avg}=\frac{1}{t_2-t_1} \int_{t_1}^{t_2} |x(t)|^2\ dt \!</math>
 
For CT functions, the power of a signal from <math>t_1\!</math> to <math>t_2\!</math> is given by the function <math>P_{avg}=\frac{1}{t_2-t_1} \int_{t_1}^{t_2} |x(t)|^2\ dt \!</math>
 +
 +
<math>\sum{N}{n=-N}</math>

Revision as of 04:59, 5 September 2008

Signal Energy

Signal Energy expended from $ t_1\! $ to $ t_2\! $ for CT functions is given by the formula $ E = \int_{t_1}^{t_2} \! |x(t)|^2\ dt $

The total signal energy for a signal can be found by taking the limits for the integral $ t_1\! $ and $ t_2\! $ as $ -inf\! $ and $ inf\! $ respectively

Signal Power

For CT functions, the power of a signal from $ t_1\! $ to $ t_2\! $ is given by the function $ P_{avg}=\frac{1}{t_2-t_1} \int_{t_1}^{t_2} |x(t)|^2\ dt \! $

$ \sum{N}{n=-N} $

Alumni Liaison

EISL lab graduate

Mu Qiao