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| + | [[Category:problem solving]] | ||
| + | [[Category:ECE301]] | ||
| + | [[Category:ECE]] | ||
| + | [[Category:Fourier series]] | ||
| + | [[Category:signals and systems]] | ||
| + | |||
| + | == Example of Computation of Fourier series of a CT SIGNAL == | ||
| + | A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]] | ||
| + | ---- | ||
Let us take the periodic, CT signal: <math>3cos(4\pi t) + e^{j\frac{2\pi}{5}t}</math> | Let us take the periodic, CT signal: <math>3cos(4\pi t) + e^{j\frac{2\pi}{5}t}</math> | ||
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<math> a_k = 0</math> else | <math> a_k = 0</math> else | ||
| + | ---- | ||
| + | [[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]] | ||
Latest revision as of 11:06, 16 September 2013
Example of Computation of Fourier series of a CT SIGNAL
A practice problem on "Signals and Systems"
Let us take the periodic, CT signal: $ 3cos(4\pi t) + e^{j\frac{2\pi}{5}t} $
As we know, the Fourier Series for a CT signal is written as:
$ x(t) = \sum^{\infty}_{k = -\infty}a_k e^{j k w_o t} $
Where $ a_k $ is: $ a_k = \frac{1}{T} \int^{T}_{0} x(t) e^{-j k w_o t} $
Our signal, x(t), can also be written as:
$ x(t) = \frac{3}{2}(e^{j 4 \pi t} + e^{-j 4 \pi t}) + e^{j \frac{2 \pi}{5} t} $
Solving for a:
$ a_1 = \frac{3}{2} $
$ a_{-1} = \frac{3}{2} $
$ a_2 = a_{-2} = 1 $
$ a_k = 0 $ else
