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Problem 1
 
Problem 1
a1. E = 6 so P = 0 \t
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a2. P = 6 / N  so P is infinate
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a1. by using integral over function square E = 6 so P = 0  
b. N must less than L + M - 1 \t
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a2. P = 6 / N  so P is infinite
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b. N must less than L + M - 1  
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c. 2*PI/T greater than 20000PI
 
c. 2*PI/T greater than 20000PI
so that T <= 1/10000\t
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d. We did not cover the material\t
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so that T <= 1/10000
Problem 2\t
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a. T\t
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d. We did not cover the material
b. F\t
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c. TTTF\t
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Problem 2
d. TT\t
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e. F\t
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a. F(unit circle must be in ROCK)
Problem 3:\t
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a.m = K/A\t
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b. T(summable)
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c. T F(cause of the square root) T F
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d. F(ak=a*-k) T(a-k = ak)
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e. F
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Problem 3:
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a.m = K/A
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b&c y(t) can be rewritten into 2 parts and has an energy of A^2/2 +k^2/32\t
 
b&c y(t) can be rewritten into 2 parts and has an energy of A^2/2 +k^2/32\t
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[[Back to Final Exam Sp 2005 solutions, ECE301 Spring 2013]]
Back to Final Exam Sp 2005 solutions, ECE301 Spring 2013
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Latest revision as of 06:35, 3 May 2013

Problem 1
a1. by using integral over function square E = 6 so P = 0
a2. P = 6 / N so P is infinite
b. N must less than L + M - 1
c. 2*PI/T greater than 20000PI
so that T <= 1/10000
d. We did not cover the material
Problem 2
a. F(unit circle must be in ROCK)
b. T(summable)
c. T F(cause of the square root) T F
d. F(ak=a*-k) T(a-k = ak)
e. F
Problem 3:
a.m = K/A
b&c y(t) can be rewritten into 2 parts and has an energy of A^2/2 +k^2/32\t

Back to Final Exam Sp 2005 solutions, ECE301 Spring 2013

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