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<math>\sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right)</math>
 
<math>\sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right)</math>
  
<math>\vdots</math>
+
<math>\quad\vdots</math>
  
  
 
[[Category:MA181Fall2011Bell]]
 
[[Category:MA181Fall2011Bell]]

Revision as of 21:41, 3 September 2011

Homework 2 collaboration area

$ \sum_{n=1}^N 1 = \dfrac11N $

$ \sum_{n=1}^N n = \dfrac12N\left(N+1\right) $

$ \sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right) $

$ \quad\vdots $

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