(New page: The easiest way to see this, and the solution usually given is that if you choose a door and not switch, the probability you were right is 1/3 -- there's one treasure door and 3 doors in t...)
 
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Latest revision as of 09:49, 7 October 2008

The easiest way to see this, and the solution usually given is that if you choose a door and not switch, the probability you were right is 1/3 -- there's one treasure door and 3 doors in total.

If you chose a door, then switched, you would get the treasure if the one you switched from was a dragon (ie you switched from dragon to treasure). There's two dragon doors and 3 doors in total, so this probability is 2/3.

Of course you can do it using conditional probabilities, but that would take more work than is required for this problem

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett