(New page: The total number of ways could be found by innumerating all the possible cases, which are B1 B2 B3 [5 0 0] [4 1 0] [3 2 0] [3 1 1] [2 2 1] Hence 5 is the answer.)
(No difference)

Revision as of 15:29, 28 September 2008

The total number of ways could be found by innumerating all the possible cases, which are

B1 B2 B3

[5 0 0] [4 1 0] [3 2 0] [3 1 1] [2 2 1]

Hence 5 is the answer.

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva