(New page: {| | align="left" style="padding-left: 0em;" | CTFT of a cosine |- | <math> X(f)=\mathcal{X}(2\pi f)=\pi \left[\delta (2\pi f- \omega_0) + \delta (2\pi f+ \omega_0)\right]=\frac{1}{2} \l...)
(No difference)

Revision as of 16:18, 9 September 2010

CTFT of a cosine
$ X(f)=\mathcal{X}(2\pi f)=\pi \left[\delta (2\pi f- \omega_0) + \delta (2\pi f+ \omega_0)\right]=\frac{1}{2} \left[\delta (f - \frac{\omega_0}{2\pi}) + \delta (f + \frac{\omega_0}{2\pi})\right] \ $
$ Since\ k\delta (kt)=\delta (t),\forall k\ne 0 $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood