(New page: In other words prove that: <math> {n \choose 1} + {n \choose 3} + {n \choose 5} + ... = {n \choose 0} + {n \choose 2} + {n \choose 4} + ... </math>)
(No difference)

Revision as of 22:18, 17 September 2008

In other words prove that:

$ {n \choose 1} + {n \choose 3} + {n \choose 5} + ... = {n \choose 0} + {n \choose 2} + {n \choose 4} + ... $

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