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<math>\int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|+\int_{\{|f_n|>M\}}|f|
 
<math>\int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|+\int_{\{|f_n|>M\}}|f|
\par
+
 
 
Since \int_{(0,1)}|f_n-f|\to0,
 
Since \int_{(0,1)}|f_n-f|\to0,
 
</math>
 
</math>

Revision as of 09:48, 2 July 2008

$ \int_{\{|f_n|>M\}}|f_n|\leq\int_{(0,1)}|f_n-f|+\int_{\{|f_n|>M\}}|f| Since \int_{(0,1)}|f_n-f|\to0, $

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010