(New page: Category:MA453Spring2009Walther From theorem 14.4 we know that R/A is a field if A is maximal. In this case we have R = R[x] and A = <x^2+1>, so we must show that <x^2+1> is maximal....)
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Revision as of 16:17, 25 March 2009


From theorem 14.4 we know that R/A is a field if A is maximal. In this case we have R = R[x] and A = <x^2+1>, so we must show that <x^2+1> is maximal. We can do this by observing x^2+1 = (x+i)(x-i) and neither (x+i) nor (x-i) are contained in R[x]. This means that <x^2+1> is maximal and that R[x]/<x^2+1> is a field. --Jniederh 20:17, 25 March 2009 (UTC)

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Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

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