(New page: This is the conjecture I came up: |U(r)| * |U(s)| = |U(rs)|)
(No difference)

Revision as of 17:39, 17 September 2008

This is the conjecture I came up:

|U(r)| * |U(s)| = |U(rs)|

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett