(New page: I am confused on this example that was done in class. ord(7 + 15<math>: \mathbb{Z} </math>)=4 <br> g<math>\in</math> 7+15<math>: \mathbb{Z} </math> <br> <math>g^{0} =1, g^{1} =7, g^{2}= 4...) |
(No difference)
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Revision as of 07:23, 10 September 2008
I am confused on this example that was done in class.
ord(7 + 15$ : \mathbb{Z} $)=4
g$ \in $ 7+15$ : \mathbb{Z} $
$ g^{0} =1, g^{1} =7, g^{2}= 4, g^{3}=13, g^{4}=1 $
How did we get 7,4,13, and 1 and how do we know that these are cycles?
--Akcooper 11:23, 10 September 2008 (UTC)
