(New page: The Question Asks for: P(H2|H1) P(H2|H1) = P[H2 n H1]/P[H1] So: P[H1] = Integral from 0 to 1 q(2q)dq P(H2 n H1) = Integral from 0 to 1 q^2(2q)dq Solve for both and plug into orginal eq...)
 
(No difference)

Latest revision as of 12:59, 20 October 2008

The Question Asks for: P(H2|H1)

P(H2|H1) = P[H2 n H1]/P[H1]

So: P[H1] = Integral from 0 to 1 q(2q)dq

P(H2 n H1) = Integral from 0 to 1 q^2(2q)dq

Solve for both and plug into orginal equation P(H2|H1).

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn