(New page: Once you get P[H1], all you have to do is use the definition of conditional probability like we had to use on Exam 1. Since we're finding P[H2|H1], and H2 and H1 are both events rather th...) |
(No difference)
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Latest revision as of 10:26, 20 October 2008
Once you get P[H1], all you have to do is use the definition of conditional probability like we had to use on Exam 1. Since we're finding P[H2|H1], and H2 and H1 are both events rather than continuous random variables, we can do this. We don't have to worry about finding the conditional PDF of Q given H1, making this pretty easy.
