(New page: <math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>)
 
 
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<math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>
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<math>\ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha}</math>, for Re{s} >  <math>\ - \alpha</math>

Latest revision as of 17:24, 24 November 2008

$ \ e^{\alpha t }u(t) \leftrightarrow \frac{1}{s + \alpha} $, for Re{s} > $ \ - \alpha $

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