(Honorable Mention: Amplitude Modulation with pulse-train)
 
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<math>Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega)</math>
 
<math>Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega)</math>
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<math>Y(\omega) = \frac{1}{2}(X(\omega + \omega_ct)+X(\omega + \omega_ct))</math>
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With this modulation <math>x(t)</math> is being copied and halved, one copy is shifted <math>\omega</math> while the other one is shifted <math>-\omega</math>
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===Demodulation===
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<math>y(t)\cos(\omega_ct) = x(t)\cos^2(\omega_ct)</math>
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<math>x(t)\cos^2(\omega_ct)</math> --> a lowpass filter with a height of 2 and <math>\omega_m<\omega_c<2\omega_c-\omega_m</math> --> <math>x(t)</math>
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==Honorable Mention: Amplitude Modulation with pulse-train==
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<math>c(t) = \sum_{k = -\infty}^\infty a_k e^{jk\frac{2\pi}{T}t}</math>

Latest revision as of 17:26, 17 November 2008

How it works

$ x(t)c(t)=y(t) $

Where $ x(t) $ is the "information signal" and $ c(t) $ is the "carrier"


Two Major Carriers

Complex Exponential

$ c(t) = e^{j(\omega_ct+\theta_c)} $

Sinusoidal

$ c(t) = cos(\omega_ct+\theta_c) $

    Where $ \omega_c $ is the frequency and $ \theta_c $ is the phase

Complex Exponential Modulation

$ y(t) = e^{j\omega_ct}x(t) $

$ Y(\omega)=F(e^{j\omega_ct}x(t)) $

$ Y(\omega)=\frac{1}{2\pi}F(e^{j\omega_ct})X(\omega) $

$ Y(\omega)=\frac{1}{2\pi}(2\pi \delta(\omega-\omega_c)X(\omega) $

$ Y(\omega)=X(\omega-\omega_c) $

What happens with this modulation is that the original signal $ x(t) $ and shifted in the frequency domain by $ \omega_c $

Demodulation ie. How the Heck do I get back my original signal

$ y(t)e^{-j\omega_ct}=x(t) $

Sinusodial Modulation

$ y(t) = \cos(\omega_ct)x(t) $

$ Y(\omega) = F(\cos(\omega_ct)x(t)) $

$ Y(\omega) = \frac{1}{2\pi}F(\cos(\omega_ct))F(x(t)) $

$ Y(\omega) = \frac{1}{2\pi}(\pi\delta(\omega + \omega_ct)+\pi\delta(\omega - \omega_ct))X(\omega) $

$ Y(\omega) = \frac{1}{2}(X(\omega + \omega_ct)+X(\omega + \omega_ct)) $

With this modulation $ x(t) $ is being copied and halved, one copy is shifted $ \omega $ while the other one is shifted $ -\omega $

Demodulation

$ y(t)\cos(\omega_ct) = x(t)\cos^2(\omega_ct) $

$ x(t)\cos^2(\omega_ct) $ --> a lowpass filter with a height of 2 and $ \omega_m<\omega_c<2\omega_c-\omega_m $ --> $ x(t) $

Honorable Mention: Amplitude Modulation with pulse-train

$ c(t) = \sum_{k = -\infty}^\infty a_k e^{jk\frac{2\pi}{T}t} $

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009