(Sampling theorem)
(Sampling theorem)
Line 36: Line 36:
  
 
<math> x_{p}(t) = x(t)p(t) = x(t)\sum^{\infty}_{n=-\infty}\delta(t-nT)</math>
 
<math> x_{p}(t) = x(t)p(t) = x(t)\sum^{\infty}_{n=-\infty}\delta(t-nT)</math>
<math>          = \sum^{\infty}_{n=-\infty}\x(t)delta(t-nT)</math>
+
<math>          = \sum^{\infty}_{n=-\infty}x(t)delta(t-nT)</math>
<math>          = \sum^{\infty}_{n=-\infty}\x(nT)delta(t-nT)</math>
+
<math>          = \sum^{\infty}_{n=-\infty}x(nT)delta(t-nT)</math>
  
 
Above diagram is the sampling process.
 
Above diagram is the sampling process.

Revision as of 16:33, 9 November 2008

Sampling theorem

Here is a signal, x(t) with X(w) = 0 when |W| > Wm.


With sampling period T, samples of x(t),x(nT), can be obtained , where n = 0 +-1, +-2, ....


The sampling frequency is $ \frac{2\pi}{T} $. It is called Ws.


If Ws is greater than 2Wm, x(t) can be recovered from its samples.


Here, 2Wm is called the "Nyquist rate".


To recover, first we need a filter with amplited T when |W| < Wc.


Wc has to exist between Wm and Ws-Wm.

Here is a diagram.

x(t) ------> multiply ---------> $ x_{p}(t) $

       ^
       |
       |
       |

$ p(t) = \sum^{\infty}_{n=-\infty}\delta(t-nT) $

$ x_{p}(t) = x(t)p(t) = x(t)\sum^{\infty}_{n=-\infty}\delta(t-nT) $ $ = \sum^{\infty}_{n=-\infty}x(t)delta(t-nT) $ $ = \sum^{\infty}_{n=-\infty}x(nT)delta(t-nT) $

Above diagram is the sampling process.

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Recent Math PhD now doing a post-doctorate at UC Riverside.

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