(New page: Now we know that <br> <math> x(t)</math> ⇒ <math>X(\omega)</math><br> Now suppose the input signal was multiplied by a cosine wave then the fourier transform of the wave would look a...) |
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Revision as of 10:05, 24 October 2008
Now we know that
$ x(t) $ ⇒ $ X(\omega) $
Now suppose the input signal was multiplied by a cosine wave then the fourier transform of the wave would look as follows
$ x(t)*cos(t) $ ⇒ $ \frac{\pi}{j}[\delta(\omega - \pi) - \delta(\omega + \pi)] $.
