(New page: <math>\frac {1}{T} \int_{0}^{T}|x(t)|^2 dt = \sum_{k=-\infty}{infty}|a_k|^2</math>)
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Revision as of 09:39, 15 October 2008

$ \frac {1}{T} \int_{0}^{T}|x(t)|^2 dt = \sum_{k=-\infty}{infty}|a_k|^2 $

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