(New page: <math>\frac {1}{N} \sum_{n=<N>}^{}|x[n]|^2 = \sum_{k=<N>}{}|a_k|^2</math>)
 
(No difference)

Latest revision as of 09:39, 15 October 2008

$ \frac {1}{N} \sum_{n=<N>}^{}|x[n]|^2 = \sum_{k=<N>}{}|a_k|^2 $

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