(New page: (1) <math> \sum^{\infty}_{k=-\infty} a_{k}e^{jkw_{0}t} -> 2\pi\sum^{infty}_{k=-infty}a_{k}\delta(w-kw_{0})</math>)
(No difference)

Revision as of 14:43, 10 October 2008

(1) $ \sum^{\infty}_{k=-\infty} a_{k}e^{jkw_{0}t} -> 2\pi\sum^{infty}_{k=-infty}a_{k}\delta(w-kw_{0}) $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood