(New page: ==signal == assume <math>x(t) = e^{-5t}u(t) + e^{-4(t-1)}u(t-3)</math> == answer == <math>x(w) = \int_{-\infty}^{\infty}</math>) |
(No difference)
|
Revision as of 15:24, 7 October 2008
signal
assume
$ x(t) = e^{-5t}u(t) + e^{-4(t-1)}u(t-3) $
answer
$ x(w) = \int_{-\infty}^{\infty} $
