(New page: Let us take the periodic, CT signal: <math>3cos(4\pi t) + e^{j\frac{2\pi}{5}t}</math> ---- As we know, the Fourier Series for a CT signal is written as: <math>x(t) = \sum^{\infty}_{k = ...)
(No difference)

Revision as of 09:07, 26 September 2008

Let us take the periodic, CT signal: $ 3cos(4\pi t) + e^{j\frac{2\pi}{5}t} $


As we know, the Fourier Series for a CT signal is written as:

$ x(t) = \sum^{\infty}_{k = -\infty}a_k e^{j k w_o t} $

Where $ a_k $ is: $ a_k = \frac{1}{T} \int^{T}_{0} x(t) e^{-j k w_o t} $


Our signal, x(t), can also be written as:

$ x(t) = \frac{3}{2}(e^{j 4 \pi t} + e^{-j 4 \pi t}) + e^{j \frac{2 \pi}{5} t} $

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett