(New page: == part A == <math>e^{st}\rightarrow h(t)\rightarrow H(S)e^{st}</math> <math>H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt</math>) |
(No difference)
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Revision as of 19:20, 25 September 2008
part A
$ e^{st}\rightarrow h(t)\rightarrow H(S)e^{st} $
$ H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt $
