(New page: == Fourier Series for DT signals == Let <math>x[n]\,</math> be a periodic DT signal with fundamental period N. Then <math>x[n]=\sum_{k=0}^{N-1} a_k e^{jk\frac{2\pi}{N} n}</math> where ...) |
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Revision as of 05:10, 25 September 2008
Fourier Series for DT signals
Let $ x[n]\, $ be a periodic DT signal with fundamental period N.
Then $ x[n]=\sum_{k=0}^{N-1} a_k e^{jk\frac{2\pi}{N} n} $
where $ a_k=\frac{1}{n}\sum_{n=0}^{N-1} x_n e^{-jk\frac{2\pi}{N} n} $
note that $ \frac{2\pi}{N} =\omega_0 $
