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| − | <math>x(t) = 4cos( | + | <math>x(t) = 4cos(2t) + (3j)sin(3t)\!</math> |
Revision as of 17:32, 24 September 2008
The signal
The signal I chose to use is as follows:
$ x(t) = 4cos(2t) + (3j)sin(3t)\! $
The fundamental period, denoted as $ T\! $, of this signal is $ 2\pi\! $. The fundamental frequency, denoted $ \omega_0\! $, is defined as:
$ \omega_0 = \frac{T}{2\pi}\! $
The value of this is $ \frac{2\pi}{2\pi}\! $, which coincidently, by no planning of mine, turns out to be $ 1\! $.
