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<pre>Input CT signal: x(t) = 3cost+sin2t</pre>. | <pre>Input CT signal: x(t) = 3cost+sin2t</pre>. | ||
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| − | <math> | + | =<math>3*\frac{e^jt+e^-jt}{2}+\frac{e^j2t-e^-j2t}{2}\,</math> |
| + | =<math>\frac{3}{2}e^{jt}-\frac{3}[2}e^{-jt}+\frac{1}{2}e^{j2t}-\frac{1}{2}e^{-j2t}</math> | ||
Latest revision as of 10:40, 24 September 2008
Fourier series:
Input CT signal: x(t) = 3cost+sin2t.
=$ 3*\frac{e^jt+e^-jt}{2}+\frac{e^j2t-e^-j2t}{2}\, $ =$ \frac{3}{2}e^{jt}-\frac{3}[2}e^{-jt}+\frac{1}{2}e^{j2t}-\frac{1}{2}e^{-j2t} $
