(New page: The two functions given to us happen to be part of the breakdown of cos(2t). <math>cos(2t)=e^{2jt}+e^{-2jt}</math> Referenced: Max Paganini) |
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Revision as of 06:52, 19 September 2008
The two functions given to us happen to be part of the breakdown of cos(2t).
$ cos(2t)=e^{2jt}+e^{-2jt} $
Referenced: Max Paganini
