(New page: <math>e^2jt = te^(-2jt)</math> <br> <math>e^2jt = te^(-2jt)</math> <br> =><math>\cos(2t)=\frac{e^{2jt}+e^{-2jt}}{2}</math>) |
(No difference)
|
Revision as of 16:45, 18 September 2008
$ e^2jt = te^(-2jt) $
$ e^2jt = te^(-2jt) $
=>$ \cos(2t)=\frac{e^{2jt}+e^{-2jt}}{2} $
