(New page: Here's what I did, and it seemed to work. Let me know if I forgot anything. Simply expand the original <math>Pr(x) = \left( \begin{array}{ccc} n \\ x \end{array} \right)p^{x}(1-p)^{n-x}<...) |
(No difference)
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Revision as of 16:35, 23 September 2008
Here's what I did, and it seemed to work. Let me know if I forgot anything.
Simply expand the original $ Pr(x) = \left( \begin{array}{ccc} n \\ x \end{array} \right)p^{x}(1-p)^{n-x} $.
Now, see if substituting n-x for x results in the same answer.
