(New page: <math>x(t)=e^{2jt} \to sys \to y(t)=te^{-2jt}</math> <math>x(t)=e^{-2jt} \to sys \to y(t)=te^{2jt}</math> This implies that if <math>x(t)=cos(2t)</math> then <math>y(t)=tcos(-2t)=tcos(2t...) |
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Revision as of 12:17, 18 September 2008
$ x(t)=e^{2jt} \to sys \to y(t)=te^{-2jt} $
$ x(t)=e^{-2jt} \to sys \to y(t)=te^{2jt} $
This implies that if $ x(t)=cos(2t) $ then $ y(t)=tcos(-2t)=tcos(2t) $.
