(New page: Start out by replacing the value of Y by N-X. You then get P(N-X) = (N N-X) * [P^(N-X)] * [(1-P)^(N-(N-X))] = (N N-X) * [(1-P)^X] * [P^(N-X) Then just expand the com...)
(No difference)

Revision as of 16:00, 23 September 2008

Start out by replacing the value of Y by N-X.

You then get P(N-X) = (N N-X) * [P^(N-X)] * [(1-P)^(N-(N-X))]

                   = (N N-X) * [(1-P)^X] * [P^(N-X)

Then just expand the combination and prove that it is equal to (N X).

The last step is to define a new variable P' = 1-P, which is the probability parameter for Y.

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett