(New page: I think it should be P(C) = ((n-k) over r) (1/5)^r * (1 - 1/5)^(n-k-r) E[C]=((n-k) over r) (1/5)^r * (1 - 1/5)^(n-k-r)*1)
 
(No difference)

Latest revision as of 15:42, 23 September 2008

I think it should be

P(C) = ((n-k) over r) (1/5)^r * (1 - 1/5)^(n-k-r)

E[C]=((n-k) over r) (1/5)^r * (1 - 1/5)^(n-k-r)*1

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood