(New page: Here we see that when the system input is <math> X_k[n]=\delta[n-k]\,</math> we get the following system output <math> Y_k[n]=(k+1)^2 \delta[n-(k+1)] \,</math> Hence if the input is ...) |
(No difference)
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Revision as of 13:02, 12 September 2008
Here we see that when the system input is $ X_k[n]=\delta[n-k]\, $ we get the following system output $ Y_k[n]=(k+1)^2 \delta[n-(k+1)] \, $
Hence if the input is
- $ X_k[n-n0]=\delta[n-n0-k]\, $ then the output shall be as follows
- $ Y_k[n-n0]=(k+1)^2 \delta[n-n0-(k+1)] \, $
